Projectile Time Of Flight

Question

A projectile is fired with speed 25 m/s at 45°. Find its time of flight (g = 10 m/s²).

RankGuru · Accepted Answer

1. **Concept**: Time of flight ($T$) is the total time the projectile remains in the air between launch and landing on the same horizontal level.
2. **Formula**: $T = \frac{2 u \sin 	heta}{g}$.
3. **Given Values**:
   - $u = 25$ m/s, $	heta = 45^\circ$, $g = 10 	ext{ m/s}^2$.
4. **Step-by-Step Calculation**:
   - $T = \frac{2 	imes 25 	imes \sin(45^\circ)}{10}$
   - $T = \frac{50 	imes 0.707}{10} = 5 	imes 0.707$
   - $T = 3.535$ s.
5. **Final Result**: Rounded to one decimal place, the time is **$3.5$ s**.

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Projectile Time Of Flight

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