Projectile Time Of Flight
Mediumphysics
A projectile is fired with speed 25 m/s at 45°. Find its time of flight (g = 10 m/s²).
Select the correct option:
Solution
Incorrect! Answer:
3.5 s
- Concept: Time of flight (T) is the total time the projectile remains in the air between launch and landing on the same horizontal level.
- Formula: T=g2usinθ.
- Given Values:
- u=25 m/s, θ=45∘, g=10 m/s2.
- Step-by-Step Calculation:
- T=102×25×sin(45∘)
- T=1050×0.707=5×0.707
- T=3.535 s.
- Final Result: Rounded to one decimal place, the time is 3.5 s.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- projectile time of flight
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
3.5 s
- Concept: Time of flight (T) is the total time the projectile remains in the air between launch and landing on the same horizontal level.
- Formula: T=g2usinθ.
- Given Values:
- u=25 m/s, θ=45∘, g=10 m/s2.
- Step-by-Step Calculation:
- T=102×25×sin(45∘)
- T=1050×0.707=5×0.707
- T=3.535 s.
- Final Result: Rounded to one decimal place, the time is 3.5 s.
This medium difficulty physics question is from the chapter kinematics, covering the topic of projectile time of flight. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse kinematics questions on RankGuru.