Projectile Motion

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A projectile is fired at 20 m/s at 30° above horizontal. Time of flight (g=10 m/s²) is:

RankGuru · Accepted Answer

For a projectile fired with initial velocity $u$ at an angle $	heta$, the time of flight $T$ is given by:
$T = \frac{2 u \sin 	heta}{g}$
Given:
- $u = 20 	ext{ m/s}$
- $	heta = 30^\circ \implies \sin 30^\circ = 0.5$
- $g = 10 	ext{ m/s}^2$
Substituting the values:
$T = \frac{2 	imes 20 	imes 0.5}{10} = \frac{20}{10} = 2.0 	ext{ s}$.

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