Projectile Motion
Maximum height reached by the projectile of KN-003 is:
Select the correct option:
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About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- projectile motion
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
5 m
From KN-003, u=20 m/s and θ=30∘. The formula for maximum height Hmax is: Hmax=2gu2sin2θ Substituting values:
- sin30∘=0.5⟹sin230∘=0.25
- u2=400
- 2g=20 Hmax=20400×0.25=20100=5 m.
This medium difficulty physics question is from the chapter kinematics, covering the topic of projectile motion. It appeared in the 2025 exam.
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