Projectile Motion (range)
A projectile is launched with speed 20 m/s at 30° above horizontal. Ignore air resistance. What is its range? (g = 10 m/s²)
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About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- projectile motion (range)
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
34.6 m
- Identify Projectile Variables:
- Initial speed (u) =20 m/s
- Angle (θ) =30∘
- Acceleration (g) =10 m/s2
- Range Formula: Horizontal range R=gu2sin(2θ).
- Calculate Trigonometric term: sin(2×30∘)=sin(60∘)=23≈0.866.
- Numerical Substitution:
- R=10202×0.866
- R=10400×0.866=40×0.866=34.64 m.
- Final Result: The range is approximately 34.6 m.
This medium difficulty physics question is from the chapter kinematics, covering the topic of projectile motion (range). It appeared in the 2025 exam.
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