Projectile Max Height
Easyphysics
A ball is projected vertically upward with speed 18 m/s. Maximum height reached? (g = 9.8 m/s² ~ use 10 m/s² for simplicity)
Select the correct option:
Solution
Incorrect! Answer:
16.2 m
- Point of Interest: At maximum height (H), the velocity of the ball is momentarily zero (v=0).
- Kinematic Equation: v2=u2−2gH.
- Constants: Initial velocity (u) =18 m/s, g=10 m/s2.
- Calculation:
- 0=182−2×10×H
- 20H=324
- H=20324=16.2 m.
- Verification: Using g=9.8 would give H≈16.5 m, but the simplified 16.2 m is the intended answer for many competitive exams.
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About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- projectile max height
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
16.2 m
- Point of Interest: At maximum height (H), the velocity of the ball is momentarily zero (v=0).
- Kinematic Equation: v2=u2−2gH.
- Constants: Initial velocity (u) =18 m/s, g=10 m/s2.
- Calculation:
- 0=182−2×10×H
- 20H=324
- H=20324=16.2 m.
- Verification: Using g=9.8 would give H≈16.5 m, but the simplified 16.2 m is the intended answer for many competitive exams.
This easy difficulty physics question is from the chapter kinematics, covering the topic of projectile max height. It appeared in the 2025 exam.
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