Skip to content

Potentiometer

Mediumphysics

A potentiometer wire balances the EMF of one cell at a length of 240 cm and that of a second cell at 160 cm under identical conditions. What is the ratio of the two EMFs?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

More current electricity Practice Questions

MediumNEET

A potentiometer is preferred over an ordinary voltmeter for measuring the emf of a cell, and a stude...

View Solution→
MediumJEE_ADVANCED

A potentiometer wire of length 10 m has a resistance of 20 Ω. If a cell of EMF 2 V is balanced at 40...

View Solution→
EasyJEE_MAIN

In a potentiometer experiment, the balancing length for a cell of EMF 1.5V is 60cm. If the cell is r...

View Solution→
MediumNEET

Three identical cells, each with internal resistance 0.6 ohm, are connected in parallel to reduce th...

View Solution→
HardNEET

A battery of emf 12 volts and internal resistance 3 ohm drives a variable load resistor, so for what...

View Solution→
HardNEET

Engineers relate the current density inside a conductor to the local electric field through the mate...

View Solution→
EasyNEET

An electric heater rated to carry 5 amperes operates across a 220 volt mains supply in a kitchen, so...

View Solution→
MediumNEET

Current passes through a 20 ohm resistor at 2 amperes for 5 minutes in a demonstration, so how much ...

View Solution→
MediumNEET

Four identical cells, each of emf 1.5 volts and internal resistance 0.2 ohm, are connected in series...

View Solution→
EasyNEET

Two resistors of 6 ohm and 3 ohm are wired side by side between the same two nodes of a circuit, so ...

View Solution→
MediumNEET

A cell of emf 6 volts and internal resistance 0.5 ohm is connected to an external resistor of 2.5 oh...

View Solution→
MediumNEET

While measuring a battery on a test bench, its terminal voltage drops from 12 volts on open circuit ...

View Solution→

Browse all current electricity questions →

About This Question

Subject
physics
Chapter
current electricity
Topic
potentiometer
Difficulty
Medium
Year
2025
Tags
potentiometerEMF comparisonbalancing lengthpotential gradientnull method

Solution

Correct Answer:

3 : 2

A potentiometer works on the principle that, for a steady current through a uniform wire, the potential drop is directly proportional to the length of wire. At the balance point no current is drawn from the cell under test, so the cell's true EMF is compared without any internal-resistance error, giving (\frac{\varepsilon_1}{\varepsilon_2} = \frac{l_1}{l_2}). Substituting the balancing lengths (l_1 = 240) cm and (l_2 = 160) cm gives (\frac{\varepsilon_1}{\varepsilon_2} = \frac{240}{160} = \frac{3}{2}), i.e. 3 : 2. The ratio 2 : 3 simply inverts the correct proportion. The ratio 4 : 3 comes from misreducing 240 : 160. The ratio 8 : 5 arises from an arithmetic slip in simplification. This is the NCERT comparison-of-EMF method using a potentiometer. A plausibility check confirms it: the cell balanced over the longer wire length must have the greater EMF, so the ratio must exceed unity, and 3 : 2 satisfies this expectation neatly. The genuine strength of the potentiometer over an ordinary voltmeter is that, by drawing zero current at balance, it imposes no loading on the cell, so the comparison reflects the true EMFs rather than terminal voltages diminished by internal-resistance drops, which is exactly why it is the preferred laboratory instrument for accurate EMF comparison.

This medium difficulty physics question is from the chapter current electricity, covering the topic of potentiometer. It appeared in the 2025 exam.

Looking for more practice? Explore all physics questions or browse current electricity questions on RankGuru.