Potentiometer
A potentiometer wire balances the EMF of one cell at a length of 240 cm and that of a second cell at 160 cm under identical conditions. What is the ratio of the two EMFs?
Select the correct option:
Solution
3 : 2
A potentiometer works on the principle that, for a steady current through a uniform wire, the potential drop is directly proportional to the length of wire. At the balance point no current is drawn from the cell under test, so the cell's true EMF is compared without any internal-resistance error, giving (\frac{\varepsilon_1}{\varepsilon_2} = \frac{l_1}{l_2}). Substituting the balancing lengths (l_1 = 240) cm and (l_2 = 160) cm gives (\frac{\varepsilon_1}{\varepsilon_2} = \frac{240}{160} = \frac{3}{2}), i.e. 3 : 2. The ratio 2 : 3 simply inverts the correct proportion. The ratio 4 : 3 comes from misreducing 240 : 160. The ratio 8 : 5 arises from an arithmetic slip in simplification. This is the NCERT comparison-of-EMF method using a potentiometer. A plausibility check confirms it: the cell balanced over the longer wire length must have the greater EMF, so the ratio must exceed unity, and 3 : 2 satisfies this expectation neatly. The genuine strength of the potentiometer over an ordinary voltmeter is that, by drawing zero current at balance, it imposes no loading on the cell, so the comparison reflects the true EMFs rather than terminal voltages diminished by internal-resistance drops, which is exactly why it is the preferred laboratory instrument for accurate EMF comparison.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More potentiometer Practice Questions
A potentiometer is preferred over an ordinary voltmeter for measuring the emf of a cell, and a stude...
A potentiometer is preferred over an ordinary voltmeter for measuring the emf of a cell, and a stude...
A potentiometer is often preferred over a voltmeter for measuring the emf of a cell accurately, so w...
A potentiometer is often preferred over a voltmeter for measuring the emf of a cell accurately, so w...
Potentiometer preferred over voltmeter for measuring emf because?
Potentiometer preferred over voltmeter for measuring emf because?
A potentiometer wire of length 10 m has a resistance of 20 Ω. If a cell of EMF 2 V is balanced at 40...
A potentiometer wire of length 10 m has a resistance of 20 Ω. If a cell of EMF 2 V is balanced at 40...
Potentiometer measures EMF accurately because it draws:
Potentiometer measures EMF accurately because it draws:
About This Question
- Subject
- physics
- Chapter
- current electricity
- Topic
- potentiometer
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
3 : 2
A potentiometer works on the principle that, for a steady current through a uniform wire, the potential drop is directly proportional to the length of wire. At the balance point no current is drawn from the cell under test, so the cell's true EMF is compared without any internal-resistance error, giving (\frac{\varepsilon_1}{\varepsilon_2} = \frac{l_1}{l_2}). Substituting the balancing lengths (l_1 = 240) cm and (l_2 = 160) cm gives (\frac{\varepsilon_1}{\varepsilon_2} = \frac{240}{160} = \frac{3}{2}), i.e. 3 : 2. The ratio 2 : 3 simply inverts the correct proportion. The ratio 4 : 3 comes from misreducing 240 : 160. The ratio 8 : 5 arises from an arithmetic slip in simplification. This is the NCERT comparison-of-EMF method using a potentiometer. A plausibility check confirms it: the cell balanced over the longer wire length must have the greater EMF, so the ratio must exceed unity, and 3 : 2 satisfies this expectation neatly. The genuine strength of the potentiometer over an ordinary voltmeter is that, by drawing zero current at balance, it imposes no loading on the cell, so the comparison reflects the true EMFs rather than terminal voltages diminished by internal-resistance drops, which is exactly why it is the preferred laboratory instrument for accurate EMF comparison.
This medium difficulty physics question is from the chapter current electricity, covering the topic of potentiometer. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse current electricity questions on RankGuru.