Potentiometer
In a potentiometer experiment, the balancing length for a cell of EMF 1.5V is 60cm. If the cell is replaced by another cell of EMF E, the balancing length becomes 80cm. The value of E is:
Select the correct option:
Solution
2.0 V
- Potentiometer Principle: For a cell of EMF E, the balancing length L follows E∝L⟹E2E1=L2L1.
- Identify Given Values: E1=1.5 V, L1=60 cm, and L2=80 cm.
- Calculation: E2=E1×L1L2=1.5×6080=1.5×34=2.0 V
- Conclusion: The EMF of the second cell is 2.0 V.
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About This Question
- Subject
- physics
- Chapter
- current electricity
- Topic
- potentiometer
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
2.0 V
- Potentiometer Principle: For a cell of EMF E, the balancing length L follows E∝L⟹E2E1=L2L1.
- Identify Given Values: E1=1.5 V, L1=60 cm, and L2=80 cm.
- Calculation: E2=E1×L1L2=1.5×6080=1.5×34=2.0 V
- Conclusion: The EMF of the second cell is 2.0 V.
This easy difficulty physics question is from the chapter current electricity, covering the topic of potentiometer. It appeared in the 2025 exam.
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