Percentage Composition
The percentage of nitrogen by mass in urea (NH₂CONH₂) is approximately: (N = 14, H = 1, C = 12, O = 16)
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- percentage composition
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
46.7%
- Write the Molecular Formula: Urea is CH4N2O (or equivalently (NH2)2CO).
- Calculate Molar Mass:
- M=12+4(1)+2(14)+16=12+4+28+16=60 g/mol.
- Find Mass of Nitrogen in One Mole:
- There are 2 nitrogen atoms per molecule.
- Mass of N = 2×14=28 g.
- Calculate Percentage:
- %N=6028×100=46.67%.
- Why This Matters: Urea's high nitrogen content makes it an efficient agricultural fertilizer. Percentage composition calculations help compare the nutrient value of different fertilizers — a common NEET application.
This easy difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of percentage composition. It appeared in the 2025 exam.
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