Dalton's Law And Laws Of Chemical Combination
According to the Law of Multiple Proportions, if carbon forms two oxides with oxygen where one oxide contains 57.1% oxygen, which of the following is the percentage of oxygen in the other oxide, assuming the simpler ratio for carbon dioxide?
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- dalton's law and laws of chemical combination
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
72.7%
The Law of Multiple Proportions states that when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in a simple whole-number ratio. The first oxide has 57.1% oxygen and 42.9% carbon. For a fixed mass of carbon (42.9 parts), the oxygen is 57.1 parts. In the second oxide (carbon dioxide, (\text{CO}_2)), the ratio is C:O (= 12:32 = 3:8), so oxygen (= 8/(3+8) \times 100 = 72.7%). The ratio of oxygen in the two oxides for the same amount of carbon: (57.1:72.7 \approx 4:5.09), which is not exactly 1:2 but illustrates the principle. More precisely, the first oxide is CO (carbon monoxide: (12:16), oxygen = (16/28 \times 100 = 57.1%)) and the second is (\text{CO}2) (oxygen (= 32/44 \times 100 = 72.7%)); the ratio of oxygen for fixed carbon (= 16:32 = 1:2). Option 40.0% corresponds to no common binary oxide of carbon. Option 50.0% would require equal masses of C and O, inconsistent with known oxides. Option 66.7% would be an oxide (\text{CO}{1.5}), which is non-integer and unrealistic. NCERT covers the Law of Multiple Proportions with CO and (\text{CO}_2) as the canonical example. Plausibility check: (\text{CO}_2) contains (32/44 \times 100 = 72.7%) oxygen by mass, matching the correct option.
This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of dalton's law and laws of chemical combination. It appeared in the 2025 exam.
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