molarity and molality

Question

A solution has molarity 1 M and density 1.05 g/mL. If the molar mass of solute is 60 g/mol, the molality is approximately:

RankGuru · Accepted Answer

1. **Analyze $1 	ext{ L}$ of solution**:
- Moles of solute $= 1 	ext{ mol}$.
- Mass of solute $= 1 	imes 60 = 60 	ext{ g}$.
- Mass of solution $= V 	imes d = 1000 	ext{ mL} 	imes 1.05 	ext{ g/mL} = 1050 	ext{ g}$.
2. **Mass of Solvent**:
- Mass of solvent $= 1050 - 60 = 990 	ext{ g} = 0.99 	ext{ kg}$.
3. **Molality ($m$)**:
- $m = \frac{	ext{Moles of solute}}{	ext{Mass of solvent in kg}} = \frac{1}{0.99} \approx 1.01 	ext{ m}$.

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