Molarity And Molality
Hardchemistry
A solution has molarity 1 M and density 1.05 g/mL. If the molar mass of solute is 60 g/mol, the molality is approximately:
Select the correct option:
Solution
Incorrect! Answer:
1.01 m
- Analyze 1 L of solution:
- Moles of solute =1 mol.
- Mass of solute =1×60=60 g.
- Mass of solution =V×d=1000 mL×1.05 g/mL=1050 g.
- Mass of Solvent:
- Mass of solvent =1050−60=990 g=0.99 kg.
- Molality (m):
- m=Mass of solvent in kgMoles of solute=0.991≈1.01 m.
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About This Question
- Subject
- chemistry
- Chapter
- solutions
- Topic
- molarity and molality
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
1.01 m
- Analyze 1 L of solution:
- Moles of solute =1 mol.
- Mass of solute =1×60=60 g.
- Mass of solution =V×d=1000 mL×1.05 g/mL=1050 g.
- Mass of Solvent:
- Mass of solvent =1050−60=990 g=0.99 kg.
- Molality (m):
- m=Mass of solvent in kgMoles of solute=0.991≈1.01 m.
This hard difficulty chemistry question is from the chapter solutions, covering the topic of molarity and molality. It appeared in the 2025 exam.
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