Molarity And Molality

Question

The molality of a solution prepared by dissolving 18 g of glucose (C₆H₁₂O₆) in 100 g of water is:

RankGuru · Accepted Answer

**Molality ($m$)** = $\frac{	ext{moles of solute}}{	ext{Mass of solvent (kg)}}$
1. **Find Moles of Glucose**:
   - Molar mass $= 180 	ext{ g/mol}$.
   - $	ext{Moles} = 18 / 180 = 0.1 	ext{ mol}$.
2. **Find Molality**:
   - Mass of water $= 100 	ext{ g} = 0.1 	ext{ kg}$.
   - $m = 0.1 / 0.1 = 1.0 	ext{ m}$ (molal).

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