Molarity And Molality
The molality of a solution prepared by dissolving 18 g of glucose (C₆H₁₂O₆) in 100 g of water is:
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- molarity and molality
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
1.0 m
Molality (m) = Mass of solvent (kg)moles of solute
- Find Moles of Glucose:
- Molar mass =180 g/mol.
- Moles=18/180=0.1 mol.
- Find Molality:
- Mass of water =100 g=0.1 kg.
- m=0.1/0.1=1.0 m (molal).
This easy difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of molarity and molality. It appeared in the 2025 exam.
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