molarity and molality

Question

The molality of a solution prepared by dissolving 18 g of glucose (C₆H₁₂O₆) in 100 g of water is:

RankGuru · Accepted Answer

**Molality ($m$)** = $\frac{	ext{moles of solute}}{	ext{Mass of solvent (kg)}}$
1. **Find Moles of Glucose**:
   - Molar mass $= 180 	ext{ g/mol}$.
   - $	ext{Moles} = 18 / 180 = 0.1 	ext{ mol}$.
2. **Find Molality**:
   - Mass of water $= 100 	ext{ g} = 0.1 	ext{ kg}$.
   - $m = 0.1 / 0.1 = 1.0 	ext{ m}$ (molal).

Rank Guru

molarity and molality

Select the correct option:

More molarity and molality Practice Questions

A solution has molarity 1 M and density 1.05 g/mL. If the molar mass of solute is 60 g/mol, the mola...

What is the molarity of a solution containing 9.8 g of H₂SO₄ in 500 mL of solution?