Integrated Rate Law
Easychemistry
For a first-order reaction, the integrated rate law is:
Select the correct option:
Solution
Incorrect! Answer:
ln[A] = ln[A]₀ - kt
For a First-Order Reaction: −dtd[A]=k[A] Separating variables and integrating: ∫[A]0[A]t[A]d[A]=−∫0tkdt ln[A]t−ln[A]0=−kt⟹ln[A]t=ln[A]0−kt
- This can also be written in exponential form: [A]t=[A]0e−kt.
- Or in common logarithms: t=k2.303log[A]t[A]0.
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About This Question
- Subject
- chemistry
- Chapter
- chemical kinetics
- Topic
- integrated rate law
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
ln[A] = ln[A]₀ - kt
For a First-Order Reaction: −dtd[A]=k[A] Separating variables and integrating: ∫[A]0[A]t[A]d[A]=−∫0tkdt ln[A]t−ln[A]0=−kt⟹ln[A]t=ln[A]0−kt
- This can also be written in exponential form: [A]t=[A]0e−kt.
- Or in common logarithms: t=k2.303log[A]t[A]0.
This easy difficulty chemistry question is from the chapter chemical kinetics, covering the topic of integrated rate law. It appeared in the 2025 exam.
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