Integrated Rate Law First Order
Easychemistry
Integrated first-order rate law (A → products) is:
Select the correct option:
Solution
Incorrect! Answer:
ln[A] = −kt + ln[A]0
- Differential Law: −dtd[A]=k[A].
- Integration:
- ∫[A]d[A]=−∫kdt
- ln[A]=−kt+I, where I is the integration constant.
- Boundary Condition: At t=0,[A]=[A]0⟹I=ln[A]0.
- Final Form: ln[A]=−kt+ln[A]0.
- Exponential Form: [A]=[A]0e−kt.
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About This Question
- Subject
- chemistry
- Chapter
- chemical kinetics
- Topic
- integrated rate law first order
- Difficulty
- Easy
- Year
- 2025
This easy difficulty chemistry question is from the chapter chemical kinetics, covering the topic of integrated rate law first order. It appeared in the 2025 exam. Practice this and similar questions to strengthen your understanding of chemical kinetics concepts.
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