Instrument Use (vernier)
Main scale division = 1 mm. 10 vernier divisions coincide with 9 main scale divisions. Least count is:
Select the correct option:
Solution
0.1 mm
The Least Count (LC) of a Vernier Calliper is the difference between one Main Scale Division (MSD) and one Vernier Scale Division (VSD): LC=1MSD−1VSD Given:
- 1MSD=1 mm.
- 10VSD=9MSD=9 mm⟹1VSD=0.9 mm. LC=1 mm−0.9 mm=0.1 mm.
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About This Question
- Subject
- physics
- Chapter
- physics and measurement
- Topic
- instrument use (vernier)
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.1 mm
The Least Count (LC) of a Vernier Calliper is the difference between one Main Scale Division (MSD) and one Vernier Scale Division (VSD): LC=1MSD−1VSD Given:
- 1MSD=1 mm.
- 10VSD=9MSD=9 mm⟹1VSD=0.9 mm. LC=1 mm−0.9 mm=0.1 mm.
This easy difficulty physics question is from the chapter physics and measurement, covering the topic of instrument use (vernier). It appeared in the 2025 exam.
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