Significant Figures In Multiplication
A surveyor multiplies a measured length of 4.2 m by a measured width of 3.15 m to find the area of a rectangular plot. How many significant figures should the reported area contain?
Select the correct option:
Solution
2
NCERT Class 11, Chapter 2 (Units and Measurements) states that in multiplication or division the result should retain only as many significant figures as the factor having the fewest significant figures. The length 4.2 m has two significant figures, while the width 3.15 m has three. The smaller count, two, controls the result. The raw product is 4.2 × 3.15 = 13.23 m^2, which must be rounded to two significant figures, giving 13 m^2. The option 3 is wrong because it borrows precision from the more precise width measurement. The option 4 is wrong as no factor has four significant figures to justify it. The option 1 is wrong since both measurements clearly contain more than a single reliable digit. A sanity check confirms that rounding 13.23 to two significant figures yields 13, which sensibly reflects the precision limit set by the coarser length measurement.
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About This Question
- Subject
- physics
- Chapter
- physics and measurement
- Topic
- significant figures in multiplication
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
2
NCERT Class 11, Chapter 2 (Units and Measurements) states that in multiplication or division the result should retain only as many significant figures as the factor having the fewest significant figures. The length 4.2 m has two significant figures, while the width 3.15 m has three. The smaller count, two, controls the result. The raw product is 4.2 × 3.15 = 13.23 m^2, which must be rounded to two significant figures, giving 13 m^2. The option 3 is wrong because it borrows precision from the more precise width measurement. The option 4 is wrong as no factor has four significant figures to justify it. The option 1 is wrong since both measurements clearly contain more than a single reliable digit. A sanity check confirms that rounding 13.23 to two significant figures yields 13, which sensibly reflects the precision limit set by the coarser length measurement.
This medium difficulty physics question is from the chapter physics and measurement, covering the topic of significant figures in multiplication. It appeared in the 2025 exam.
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