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Inert Pair Effect

Hardchemistry

Why does lead show a more stable +2 oxidation state than +4 while carbon at the top of the same group prefers a +4 state?

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About This Question

Subject
chemistry
Chapter
classification of elements and periodicity in properties
Topic
inert pair effect
Difficulty
Hard
Year
2025
Tags
inert pair effectoxidation state stabilitylead chemistrygroup 14 trends electron pair

Solution

Correct Answer:

The inert pair effect stabilises the lower oxidation state in heavier elements

The inert pair effect is the reluctance of the outermost ns^2 pair of electrons to participate in bonding among the heavier elements of Groups 13 to 16. As one moves down a group, the ns electrons become increasingly held in place because of poor shielding by intervening d and f electrons, which causes weak penetration and reduced bonding tendency of the s pair. In lead, the 6s^2 pair tends to remain inert, so the +2 oxidation state, which uses only the two p electrons, becomes more stable than the +4 state that would also require the s pair. Carbon, lacking these inner d and f electrons, readily uses all four valence electrons and prefers the +4 state. The option that lead is more electronegative is false. The option that carbon is a metal is incorrect, since carbon is a non-metal. The option of fewer valence electrons is wrong, as both have four. This effect is a key JEE Advanced periodicity concept. Plausibility check: the stability order Sn^4+ > Pb^2+ and the oxidising nature of PbO_2 confirm the inert pair stabilisation of lead's lower state.

This hard difficulty chemistry question is from the chapter classification of elements and periodicity in properties, covering the topic of inert pair effect. It appeared in the 2025 exam.

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