Ideal Transformer

As given in NCERT Class 12, Chapter 7 (Alternating Current), an ideal transformer conserves power and relates primary and secondary voltages to turns through $\frac{V_s}{V_p}=\frac{N_s}{N_p}$, because the same flux links every turn of both windings. Rearranging: $V_s=V_p\times \frac{N_s}{N_p}=220\times \frac{200}{1000}=220\times 0.2=44\text{V}$. The option 1100 V inverts the ratio, treating the device as a step-up transformer. The option 22 V uses a turns ratio of one-tenth instead of one-fifth. The option 88 V mistakenly uses a ratio of 0.4. A plausibility check confirms that for a step-down transformer the secondary voltage must be smaller than the primary, and 44 V is indeed below 220 V, matching the turns ratio of 1:5. Since the transformer is ideal, the secondary current correspondingly rises to keep the power product $VI$ unchanged between the two sides.