Capacitive Reactance
In an AC circuit, a capacitor of capacitance 25 microfarads is connected to a source whose frequency is 50 hertz. What is the capacitive reactance offered by the capacitor, taking pi as 3.14?
Select the correct option:
Solution
127 ohm
As described in NCERT Class 12, Chapter 7 (Alternating Current), a capacitor opposes alternating current through its capacitive reactance XC=ωC1=2πfC1, which decreases with frequency because a rapidly alternating voltage keeps the capacitor charging and discharging without fully blocking flow. Substituting f=50 Hz and C=25×10−6 F: the denominator is 2πfC=2×3.14×50×25×10−6=7.85×10−3, giving XC=7.85×10−31≈127 Ω. The option 318 ohm forgets the factor of 2 in 2π. The option 63.7 ohm doubles the frequency incorrectly. The option 254 ohm multiplies the true value by two. A sanity check confirms units of (s−1)(F)1=Ω, and unlike an inductor, a capacitor's reactance falls as frequency rises, so it blocks DC but readily passes high-frequency AC. This behaviour is the exact opposite of an inductor, whose reactance grows with frequency, and this complementary property is what allows LC combinations to select particular frequencies. Physically, the reactance is not a true resistance because the capacitor dissipates no energy; it merely stores charge and returns it, imposing an opposition that depends on how quickly the applied voltage reverses. At the given 50 Hz mains frequency, a reactance of about 127 ohm means this capacitor would limit the current substantially, which is why capacitors of this size are common in power-line filtering and phase-correction applications.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More capacitive reactance Practice Questions
About This Question
- Subject
- physics
- Chapter
- electromagnetic induction and alternating currents
- Topic
- capacitive reactance
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
127 ohm
As described in NCERT Class 12, Chapter 7 (Alternating Current), a capacitor opposes alternating current through its capacitive reactance XC=ωC1=2πfC1, which decreases with frequency because a rapidly alternating voltage keeps the capacitor charging and discharging without fully blocking flow. Substituting f=50 Hz and C=25×10−6 F: the denominator is 2πfC=2×3.14×50×25×10−6=7.85×10−3, giving XC=7.85×10−31≈127 Ω. The option 318 ohm forgets the factor of 2 in 2π. The option 63.7 ohm doubles the frequency incorrectly. The option 254 ohm multiplies the true value by two. A sanity check confirms units of (s−1)(F)1=Ω, and unlike an inductor, a capacitor's reactance falls as frequency rises, so it blocks DC but readily passes high-frequency AC. This behaviour is the exact opposite of an inductor, whose reactance grows with frequency, and this complementary property is what allows LC combinations to select particular frequencies. Physically, the reactance is not a true resistance because the capacitor dissipates no energy; it merely stores charge and returns it, imposing an opposition that depends on how quickly the applied voltage reverses. At the given 50 Hz mains frequency, a reactance of about 127 ohm means this capacitor would limit the current substantially, which is why capacitors of this size are common in power-line filtering and phase-correction applications.
This medium difficulty physics question is from the chapter electromagnetic induction and alternating currents, covering the topic of capacitive reactance. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse electromagnetic induction and alternating currents questions on RankGuru.