Hydrogen Bonding
Intramolecular hydrogen bonding in ortho-nitrophenol causes its boiling point to be lower than that of para-nitrophenol; which statement correctly explains this difference?
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Solution
Intramolecular H-bonding in ortho-nitrophenol reduces intermolecular association, while para-nitrophenol forms stronger intermolecular H-bonds
Hydrogen bonding significantly affects the physical properties of molecules, particularly boiling points. In ortho-nitrophenol, the -OH group and the -NO_2 group are on adjacent carbon atoms in the benzene ring. This close proximity allows the O-H hydrogen to form an intramolecular hydrogen bond with one of the oxygen atoms of the -NO_2 group within the same molecule. Intramolecular H-bonding forms a six-membered ring and satisfies the H-bonding tendency of the -OH group internally. As a result, ortho-nitrophenol molecules are less available to form intermolecular hydrogen bonds with neighbouring molecules, leading to weaker intermolecular association and a lower boiling point (214 degrees C). In contrast, para-nitrophenol cannot form intramolecular H-bonds because the -OH and -NO_2 groups are too far apart (on opposite ends of the ring). The -OH group is therefore free to form intermolecular hydrogen bonds with -OH groups of adjacent molecules, creating an extended network of H-bonded molecules that requires more energy to break and thus results in a higher boiling point (279 degrees C). The nitro group itself does not block all intermolecular forces; it merely changes their nature in the ortho isomer. Para-nitrophenol does not have a different molar mass (both isomers have the same molecular formula C_6H_5NO_3). Ionic and covalent distinction does not apply here as both are covalent molecular compounds. This concept is a standard NCERT Class 11 application of intra- versus intermolecular hydrogen bonding. Plausibility: the ~65-degree-C boiling point difference is experimentally confirmed and is one of the most cited examples of intramolecular H-bonding effects in JEE chemistry.
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About This Question
- Subject
- chemistry
- Chapter
- chemical bonding and molecular structure
- Topic
- hydrogen bonding
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Intramolecular H-bonding in ortho-nitrophenol reduces intermolecular association, while para-nitrophenol forms stronger intermolecular H-bonds
Hydrogen bonding significantly affects the physical properties of molecules, particularly boiling points. In ortho-nitrophenol, the -OH group and the -NO_2 group are on adjacent carbon atoms in the benzene ring. This close proximity allows the O-H hydrogen to form an intramolecular hydrogen bond with one of the oxygen atoms of the -NO_2 group within the same molecule. Intramolecular H-bonding forms a six-membered ring and satisfies the H-bonding tendency of the -OH group internally. As a result, ortho-nitrophenol molecules are less available to form intermolecular hydrogen bonds with neighbouring molecules, leading to weaker intermolecular association and a lower boiling point (214 degrees C). In contrast, para-nitrophenol cannot form intramolecular H-bonds because the -OH and -NO_2 groups are too far apart (on opposite ends of the ring). The -OH group is therefore free to form intermolecular hydrogen bonds with -OH groups of adjacent molecules, creating an extended network of H-bonded molecules that requires more energy to break and thus results in a higher boiling point (279 degrees C). The nitro group itself does not block all intermolecular forces; it merely changes their nature in the ortho isomer. Para-nitrophenol does not have a different molar mass (both isomers have the same molecular formula C_6H_5NO_3). Ionic and covalent distinction does not apply here as both are covalent molecular compounds. This concept is a standard NCERT Class 11 application of intra- versus intermolecular hydrogen bonding. Plausibility: the ~65-degree-C boiling point difference is experimentally confirmed and is one of the most cited examples of intramolecular H-bonding effects in JEE chemistry.
This medium difficulty chemistry question is from the chapter chemical bonding and molecular structure, covering the topic of hydrogen bonding. It appeared in the 2025 exam.
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