First Order De

Solve General Equation: $\frac{d y}{d x} = - y$ .
- $\frac{d y}{y} = - d x ⟹ ln y = - x + C$
- $y = e^{- x + C} = K e^{- x}$ .
Apply Initial Condition: Given $y = 1$ when $x = 0$ .
- $1 = K e^{0} = K \cdot 1$
- $K = 1$ .
Particular Solution: Substituting $K = 1$ back, we get $y = e^{- x}$ .

This medium difficulty mathematics question is from the chapter differential equations, covering the topic of first order de. It appeared in the 2025 exam.

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First Order De

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