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Order And Degree

Mediummathematics

Examine the equation \sqrt{1 + \left(\frac{dy}{dx}\right)^2} = \frac{d^2y}{dx^2} and determine the degree after rationalizing it into proper polynomial form.

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About This Question

Subject
mathematics
Chapter
differential equations
Topic
order and degree
Difficulty
Medium
Year
2025
Tags
advanced-calculus-drilldegree of ODErationalizationradical removalpolynomial form

Solution

Correct Answer:

Degree 2

Degree is defined only when a differential equation can be expressed as a polynomial in its derivatives, free of radicals and fractional powers. The given equation contains a square root over a derivative expression, so it must be rationalized before the degree can be read off. The highest-order derivative present is \frac{d^2y}{dx^2}, so the order is 2. To clear the radical, square both sides: 1 + \left(\frac{dy}{dx}\right)^2 = \left(\frac{d^2y}{dx^2}\right)^2. Now the equation is a polynomial in the derivatives, and the highest-order derivative \frac{d^2y}{dx^2} appears raised to the power 2. The degree is the power of the highest-order derivative in this rationalized polynomial form, so the degree is 2. Option Degree 1 reads the power off the original radical form before rationalizing, which is not permitted. Option Degree not defined is incorrect because squaring successfully removes the radical and yields a polynomial in the derivatives. Option Degree 3 has no basis. As a final consistency check, after rationalization the highest-order derivative \frac{d^2y}{dx^2} is squared, so the degree is well defined and equals 2.

This medium difficulty mathematics question is from the chapter differential equations, covering the topic of order and degree. It appeared in the 2025 exam.

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