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Faraday's Law Of Induction

Easyphysics

A single circular loop of area 0.02 m^2 lies in a magnetic field that rises uniformly from 0.1 T to 0.5 T in 0.2 s. What is the magnitude of the average induced EMF in the loop?

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About This Question

Subject
physics
Chapter
electromagnetic induction and alternating currents
Topic
faraday's law of induction
Difficulty
Easy
Year
2025
Tags
Faraday's lawmagnetic fluxinduced EMFrate of change of fieldsingle loop

Solution

Correct Answer:

0.04 V

Faraday's law of electromagnetic induction states that the EMF induced in a closed loop equals the negative time rate of change of magnetic flux (\Phi = BA) linking that loop. For a stationary loop of fixed area lying perpendicular to a changing field, only the field magnitude varies, so the flux change is governed entirely by (\Delta B). The average induced EMF is (|\varepsilon| = A,\dfrac{\Delta B}{\Delta t}). Substituting (A = 0.02) m^2, (\Delta B = 0.5 - 0.1 = 0.4) T and (\Delta t = 0.2) s gives (|\varepsilon| = 0.02 \times 0.4/0.2 = 0.04) V. The option 0.02 V is wrong because it uses only half the field change. The option 0.08 V incorrectly doubles the area contribution. The option 0.20 V mistakenly drops the area factor and uses (\Delta B/\Delta t) alone. This is the standard NCERT formulation of motional flux change in a fixed coil. A plausibility check confirms the unit T·m^2/s equals the volt, and the magnitude is reasonable for such a slow, weak-field variation.

This easy difficulty physics question is from the chapter electromagnetic induction and alternating currents, covering the topic of faraday's law of induction. It appeared in the 2025 exam.

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