Faraday's Law Of Induction
A single circular loop of area 0.02 m^2 lies in a magnetic field that rises uniformly from 0.1 T to 0.5 T in 0.2 s. What is the magnitude of the average induced EMF in the loop?
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About This Question
- Subject
- physics
- Chapter
- electromagnetic induction and alternating currents
- Topic
- faraday's law of induction
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.04 V
Faraday's law of electromagnetic induction states that the EMF induced in a closed loop equals the negative time rate of change of magnetic flux (\Phi = BA) linking that loop. For a stationary loop of fixed area lying perpendicular to a changing field, only the field magnitude varies, so the flux change is governed entirely by (\Delta B). The average induced EMF is (|\varepsilon| = A,\dfrac{\Delta B}{\Delta t}). Substituting (A = 0.02) m^2, (\Delta B = 0.5 - 0.1 = 0.4) T and (\Delta t = 0.2) s gives (|\varepsilon| = 0.02 \times 0.4/0.2 = 0.04) V. The option 0.02 V is wrong because it uses only half the field change. The option 0.08 V incorrectly doubles the area contribution. The option 0.20 V mistakenly drops the area factor and uses (\Delta B/\Delta t) alone. This is the standard NCERT formulation of motional flux change in a fixed coil. A plausibility check confirms the unit T·m^2/s equals the volt, and the magnitude is reasonable for such a slow, weak-field variation.
This easy difficulty physics question is from the chapter electromagnetic induction and alternating currents, covering the topic of faraday's law of induction. It appeared in the 2025 exam.
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