experimental data

Question

Five measurements of a time period: 2.13 s, 2.15 s, 2.11 s, 2.14 s, 2.12 s. Mean and absolute error (half range) are:

RankGuru · Accepted Answer

1. **Mean**: $\frac{2.13 + 2.15 + 2.11 + 2.14 + 2.12}{5} = \frac{10.65}{5} = 2.13 	ext{ s}$.
2. **Range**: Max value - Min value = $2.15 - 2.11 = 0.04 	ext{ s}$.
3. **Uncertainty (Half-Range)**: $0.04 	ext{ s} / 2 = 0.02 	ext{ s}$.
Result = $(2.13 \pm 0.02) 	ext{ s}$.

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experimental data

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