Doppler Effect
Mediumphysics
A whistle revolves in a circle with angular speed ω = 20 rad/s using a string of length 50 cm. If the frequency of sound from the whistle is 385 Hz, then what is the minimum frequency heard by an observer far away from the centre? (Velocity of sound v = 340 m/s)
Select the correct option:
Solution
Incorrect! Answer:
374 Hz
- Source Velocity (vs): vs=rω=(0.50 m)(20 rad/s)=10 m/s.
- Doppler Condition: Minimum frequency is heard when the source is moving directly AWAY from the observer.
- Formula: f′=f(v+vsv).
- Calculation: f′=385(340+10340)=385×350340=385×3534=11×34=374 Hz.
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About This Question
- Subject
- physics
- Chapter
- waves
- Topic
- doppler effect
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
374 Hz
- Source Velocity (vs): vs=rω=(0.50 m)(20 rad/s)=10 m/s.
- Doppler Condition: Minimum frequency is heard when the source is moving directly AWAY from the observer.
- Formula: f′=f(v+vsv).
- Calculation: f′=385(340+10340)=385×350340=385×3534=11×34=374 Hz.
This medium difficulty physics question is from the chapter waves, covering the topic of doppler effect. It appeared in the 2025 exam.
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