Doppler Effect
An ambulance siren emits sound at 660 Hz while the vehicle moves directly toward a stationary pedestrian at 30 m per second, with sound speed 330 m per second. What frequency does the pedestrian hear?
Select the correct option:
Solution
726 Hz
The Doppler effect changes the observed frequency when a source and observer move relative to each other. For a stationary observer and a source approaching at speed vs, the apparent frequency is f′=f(v−vsv), where v is the speed of sound. The denominator shrinks because successive wavefronts are emitted from closer positions, compressing the wavelength. Substituting f=660 Hz, v=330 m/s, and vs=30 m/s gives f′=660(330−30330)=660×300330=660×1.1=726 Hz. The value 600 Hz wrongly adds vs in the denominator, which applies to a receding source. The value 660 Hz ignores the motion entirely. The value 693 Hz comes from putting vs in the numerator using the observer-motion formula by mistake. This is the NCERT Doppler formula for a moving source. As a plausibility check, an approaching source must raise the pitch, so the heard frequency must exceed 660 Hz, and the modest 10 percent increase to 726 Hz is consistent with a source speed that is one-eleventh of the sound speed.
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About This Question
- Subject
- physics
- Chapter
- oscillations and waves
- Topic
- doppler effect
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
726 Hz
The Doppler effect changes the observed frequency when a source and observer move relative to each other. For a stationary observer and a source approaching at speed vs, the apparent frequency is f′=f(v−vsv), where v is the speed of sound. The denominator shrinks because successive wavefronts are emitted from closer positions, compressing the wavelength. Substituting f=660 Hz, v=330 m/s, and vs=30 m/s gives f′=660(330−30330)=660×300330=660×1.1=726 Hz. The value 600 Hz wrongly adds vs in the denominator, which applies to a receding source. The value 660 Hz ignores the motion entirely. The value 693 Hz comes from putting vs in the numerator using the observer-motion formula by mistake. This is the NCERT Doppler formula for a moving source. As a plausibility check, an approaching source must raise the pitch, so the heard frequency must exceed 660 Hz, and the modest 10 percent increase to 726 Hz is consistent with a source speed that is one-eleventh of the sound speed.
This medium difficulty physics question is from the chapter oscillations and waves, covering the topic of doppler effect. It appeared in the 2025 exam.
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