Concentration Terms
A solution is prepared by dissolving 34.2 g of sucrose (C₁₂H₂₂O₁₁, molar mass = 342 g mol⁻¹) in 500 mL of water. Assuming the density of the resulting solution is 1.024 g mL⁻¹ and its total volume is 505 mL, the molarity of the solution is closest to:
Select the correct option:
Solution
0.198 M
Moles of sucrose = 34.2 / 342 = 0.1 mol. Volume of solution = 505 mL = 0.505 L. Molarity = moles of solute / volume of solution in litres = 0.1 / 0.505 = 0.198 M. A common error is to use the volume of solvent (500 mL) instead of the total volume of solution (505 mL). Molarity is defined with respect to the volume of the entire solution, not just the solvent. Although the numerical difference is small here, understanding this distinction is important for precise calculations in dilute and concentrated solutions alike.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More concentration terms Practice Questions
About This Question
- Subject
- chemistry
- Chapter
- solutions
- Topic
- concentration terms
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
0.198 M
Moles of sucrose = 34.2 / 342 = 0.1 mol. Volume of solution = 505 mL = 0.505 L. Molarity = moles of solute / volume of solution in litres = 0.1 / 0.505 = 0.198 M. A common error is to use the volume of solvent (500 mL) instead of the total volume of solution (505 mL). Molarity is defined with respect to the volume of the entire solution, not just the solvent. Although the numerical difference is small here, understanding this distinction is important for precise calculations in dilute and concentrated solutions alike.
This medium difficulty chemistry question is from the chapter solutions, covering the topic of concentration terms. It appeared in the 2025 exam.
Looking for more practice? Explore all chemistry questions or browse solutions questions on RankGuru.