Concentration Terms
The molality of a solution prepared by dissolving 9.0 g of glucose (C₆H₁₂O₆, molar mass = 180 g mol⁻¹) in 500 g of water is:
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About This Question
- Subject
- chemistry
- Chapter
- some basic concepts in chemistry
- Topic
- concentration terms
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.10 m
- Recall the Definition of Molality: m=mass of solvent in kgmoles of solute.
- Calculate Moles of Glucose:
- Moles = 180 g/mol9.0 g=0.05 mol.
- Convert Solvent Mass to kg:
- Mass of water = 500 g=0.500 kg.
- Compute Molality:
- m=0.500 kg0.05 mol=0.10 mol kg−1.
- Key Point: Molality depends on the mass of solvent, not the total mass of solution, making it temperature-independent — an important distinction from molarity for NEET.
This easy difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of concentration terms. It appeared in the 2025 exam.
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