Combinations
The number of ways to select a cricket team of 11 players from 15 players, where 2 particular players must be included, is
Select the correct option:
Solution
715
- Analyze Constraints: We need a team of 11. 2 players are already selected (mandatory inclusion).
- Selection Task: We need to pick the remaining 11−2=9 players.
- Available Pool: We pick these from the remaining 15−2=13 players.
- Apply Combination: (913).
- Symmetry Property: (913)=(413).
- Calculation:
- (413)=4×3×2×113×12×11×10=213×11×10=13×11×5=715.
- Result: 715 ways.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More combinations Practice Questions
The total number of ways of selecting 4 letters from the word 'EXAMINATION' is
The total number of ways of selecting 4 letters from the word 'EXAMINATION' is
The value of C(10, 3) is
The value of C(10, 3) is
From a group of 7 men and 4 women, a committee of 5 persons is to be formed. In how many ways can th...
From a group of 7 men and 4 women, a committee of 5 persons is to be formed. In how many ways can th...
If C(n, 4) = C(n, 6), then n equals
If C(n, 4) = C(n, 6), then n equals
The number of diagonals in a polygon with n sides is
The number of diagonals in a polygon with n sides is
About This Question
- Subject
- mathematics
- Chapter
- permutations and combinations
- Topic
- combinations
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
715
- Analyze Constraints: We need a team of 11. 2 players are already selected (mandatory inclusion).
- Selection Task: We need to pick the remaining 11−2=9 players.
- Available Pool: We pick these from the remaining 15−2=13 players.
- Apply Combination: (913).
- Symmetry Property: (913)=(413).
- Calculation:
- (413)=4×3×2×113×12×11×10=213×11×10=13×11×5=715.
- Result: 715 ways.
This medium difficulty mathematics question is from the chapter permutations and combinations, covering the topic of combinations. It appeared in the 2025 exam.
Looking for more practice? Explore all mathematics questions or browse permutations and combinations questions on RankGuru.