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Combinations Equation

Easymathematics

If the combinatorial equation C(n, 2) equals 28 holds for a positive integer n, then the value of n satisfying this relation equals which number?

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About This Question

Subject
mathematics
Chapter
permutations and combinations
Topic
combinations equation
Difficulty
Easy
Year
2025
Tags
advanced-calculus-drillcombination-equationquadratic-equationpositive-integerfactorial

Solution

Correct Answer:

Solving an equation involving a single combination reduces to a quadratic in n, a routine JEE Advanced algebraic step. The relation C(n, 2) = n(n - 1)/2 = 28 gives n(n - 1) = 56. Seeking two consecutive integers with product 56, we find 8 × 7 = 56, so n = 8. Equivalently, n^2 - n - 56 = 0 factors as (n - 8)(n + 7) = 0, whose positive root is n = 8. Option 7 gives C(7,2) = 21, too small. Option 14 gives C(14,2) = 91, too large. Option 9 gives C(9,2) = 36, also incorrect. Hence n = 8. Plausibility check: substituting n = 8 yields C(8,2) = 8·7/2 = 28, exactly the required value, confirming the positive integer solution of the combination equation. The block method for togetherness conditions ties the constrained items into a single unit, arranges the resulting units, and then multiplies by the internal arrangements of the block. Its natural counterpart is the gap method for separation conditions, and recognizing which of these complementary techniques a problem demands is the central strategic decision in arrangement counting.

This easy difficulty mathematics question is from the chapter permutations and combinations, covering the topic of combinations equation. It appeared in the 2025 exam.

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