Capillary Rise
Water rises to a height of 6 cm in a narrow glass capillary tube dipped vertically into a beaker. If a second tube of half this internal radius is used in the same water, to what height will the water rise?
Select the correct option:
Solution
12 cm
Capillary action results from the interplay of surface tension and the adhesion between water and glass, which curves the meniscus and pulls the liquid column upward. The equilibrium rise is given by h=rρg2Scosθ, showing that for fixed liquid, contact angle and tube material, the height is inversely proportional to the tube radius, h∝1/r. Therefore h1r1=h2r2. With h1=6cm and r2=r1/2, we get h2=h1r2r1=6×2=12cm. The value 3 cm wrongly assumes height falls with radius. The value 6 cm ignores the change in radius altogether. The value 9 cm has no consistent proportionality. This is precisely the inverse-radius dependence derived in NCERT for capillarity, often called Jurin's law, and it holds because the upward surface-tension force scales with the circumference while the weight of the lifted column scales with the cross-sectional area. The contact angle for water on clean glass is nearly zero, so cosθ≈1 and the meniscus is almost hemispherical. As a plausibility check, a thinner tube produces a more sharply curved meniscus and a stronger lifting effect, so the narrower second tube should indeed raise the water higher, consistent with the doubled height obtained.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More capillary rise Practice Questions
About This Question
- Subject
- physics
- Chapter
- properties of solids and liquids
- Topic
- capillary rise
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
12 cm
Capillary action results from the interplay of surface tension and the adhesion between water and glass, which curves the meniscus and pulls the liquid column upward. The equilibrium rise is given by h=rρg2Scosθ, showing that for fixed liquid, contact angle and tube material, the height is inversely proportional to the tube radius, h∝1/r. Therefore h1r1=h2r2. With h1=6cm and r2=r1/2, we get h2=h1r2r1=6×2=12cm. The value 3 cm wrongly assumes height falls with radius. The value 6 cm ignores the change in radius altogether. The value 9 cm has no consistent proportionality. This is precisely the inverse-radius dependence derived in NCERT for capillarity, often called Jurin's law, and it holds because the upward surface-tension force scales with the circumference while the weight of the lifted column scales with the cross-sectional area. The contact angle for water on clean glass is nearly zero, so cosθ≈1 and the meniscus is almost hemispherical. As a plausibility check, a thinner tube produces a more sharply curved meniscus and a stronger lifting effect, so the narrower second tube should indeed raise the water higher, consistent with the doubled height obtained.
This medium difficulty physics question is from the chapter properties of solids and liquids, covering the topic of capillary rise. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse properties of solids and liquids questions on RankGuru.