Bohr Model Energy
A researcher considers a singly ionised helium ion with atomic number two behaving like a hydrogen-like system, and asks for the energy of its ground state in electronvolts.
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About This Question
- Subject
- physics
- Chapter
- atoms and nuclei
- Topic
- bohr model energy
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
-54.4 eV
For a hydrogen-like ion with a single electron, NCERT's Bohr analysis gives the energy levels as En=−13.6n2Z2 eV, where Z is the nuclear charge. The energy scales as the square of the atomic number because a larger nuclear charge binds the electron more tightly. Singly ionised helium has Z=2, and the ground state has n=1, so E1=−13.6×14=−54.4 eV. The value −13.6 eV is wrong because that is hydrogen's ground state with Z=1 and ignores the Z2 factor. The value −27.2 eV is wrong because it scales linearly with Z rather than as Z2. The value −6.8 eV is wrong because it divides rather than multiplies by Z2, loosening the binding instead of tightening it. As stated in NCERT Class 12, Chapter 12 (Atoms), hydrogen-like ions such as He+ and Li2+ follow the same Bohr formula scaled by nuclear charge, since each still has only one electron orbiting a point charge. The stronger nuclear attraction also pulls the orbits inward, shrinking the radius by a factor of Z, which is the geometric counterpart of the deeper energy. A magnitude check: doubling the charge quadruples the binding energy, so −54.4 eV being exactly four times −13.6 eV confirms the Z2 dependence.
This hard difficulty physics question is from the chapter atoms and nuclei, covering the topic of bohr model energy. It appeared in the 2025 exam.
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