Half-life And Decay Law
A radioactive isotope used in medical imaging has a half-life of 6 hours, and a technician needs its decay constant so the activity can be predicted accurately.
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About This Question
- Subject
- physics
- Chapter
- atoms and nuclei
- Topic
- half-life and decay law
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
0.1155 per hour
NCERT relates the decay constant λ, the probability per unit time that a nucleus decays, to the half-life through T1/2=λln2=λ0.693. Rearranging gives λ=T1/20.693. Substituting T1/2=6 hours, λ=60.693=0.1155 per hour. The value 0.693 per hour is wrong because it uses ln2 directly without dividing by the half-life. The value 6.0 per hour is wrong because it merely repeats the half-life with an inverted unit and ignores the logarithm factor. The value 0.0192 per hour is wrong because it divides 0.1155 by 6 again, applying the half-life twice. As stated in NCERT Class 12, Chapter 13 (Nuclei), a shorter half-life corresponds to a larger decay constant, meaning faster decay, so isotopes chosen for medical imaging are deliberately short-lived to limit patient exposure. The decay constant is the intrinsic probability per unit time that any single nucleus disintegrates, and it does not depend on how many nuclei are present. A plausibility check: multiplying λ=0.1155 per hour by the 6-hour half-life returns 0.693, recovering ln2 as required, so the value is internally consistent with the defining relation between half-life and decay constant.
This medium difficulty physics question is from the chapter atoms and nuclei, covering the topic of half-life and decay law. It appeared in the 2025 exam.
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