Arithmetic Progression
If the 3rd term of an AP is 7 and the 7th term is 23, then the 10th term is
Select the correct option:
Solution
35
- Create Equations:
- T3=a+2d=7
- T7=a+6d=23
- Solve for d: Subtract the first from the second:
- (a+6d)−(a+2d)=23−7
- 4d=16⟹d=4.
- Solve for a:
- a+2(4)=7⟹a=7−8=−1.
- Find 10th Term:
- T10=a+9d=−1+9(4)=−1+36=35.
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About This Question
- Subject
- mathematics
- Chapter
- sequence and series
- Topic
- arithmetic progression
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
35
- Create Equations:
- T3=a+2d=7
- T7=a+6d=23
- Solve for d: Subtract the first from the second:
- (a+6d)−(a+2d)=23−7
- 4d=16⟹d=4.
- Solve for a:
- a+2(4)=7⟹a=7−8=−1.
- Find 10th Term:
- T10=a+9d=−1+9(4)=−1+36=35.
This medium difficulty mathematics question is from the chapter sequence and series, covering the topic of arithmetic progression. It appeared in the 2025 exam.
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