Arithmetic Progression

Question

The 10th term of the AP 3, 7, 11, 15, ... is

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1. **Identify AP Parameters**: 
   - First term $a = 3$.
   - Common difference $d = 7 - 3 = 4$.
2. **nth Term Formula**: $T_n = a + (n - 1)d$.
3. **Calculation for $n=10$**:
   - $T_{10} = 3 + (10 - 1) 	imes 4$
   - $T_{10} = 3 + 9 	imes 4 = 3 + 36 = 39$.
4. **Result**: The 10th term is 39.

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