Amines

Easychemistry

A solution is prepared by dissolving 4.65 g of CH3NH2 (molar mass = 31 g mol-1) in water and making the volume 250 mL. The molarity of the solution is:

Select the correct option:

0.15 mol L-1

0.60 mol L-1

1.20 mol L-1

0.30 mol L-1

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About This Question

Subject: chemistry
Chapter: organic compounds containing nitrogen
Topic: amines
Difficulty: Easy
Year: 2025

Solution

Correct Answer:

0.60 mol L-1

First calculate moles of methylamine: n = mass/molar mass = 4.65/31 = 0.15 mol. The final volume is 250 mL = 0.250 L. Molarity is M = n/V = 0.15/0.250 = 0.60 mol L-1. The arithmetic is straightforward, but the key check is unit conversion from mL to L before division; without this conversion the concentration would be incorrect.

This easy difficulty chemistry question is from the chapter organic compounds containing nitrogen, covering the topic of amines. It appeared in the 2025 exam.

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Amines

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