Acid–base Equilibria
Which of the following aqueous salts gives a solution with pH ≈ 7 at 25°C?
Select the correct option:
Solution
NH4CH3COO
- Salt Hydrolysis Rules:
- Strong Acid + Strong Base (e.g., NaCl): No hydrolysis, pH=7.
- Strong Acid + Weak Base (e.g., NH4Cl): Cationic hydrolysis, pH<7 (Acidic).
- Weak Acid + Strong Base (e.g., CH3COONa): Anionic hydrolysis, pH>7 (Basic).
- Weak Acid + Weak Base (e.g., NH4CH3COO): Both ionize.
- Case of Ammonium Acetate: pH=7+21(pKa−pKb).
- Values: For acetic acid, pKa≈4.74. For ammonia, pKb≈4.75.
- Outcome: Since pKa≈pKb, the acidic and basic tendencies of the ions cancel each other out.
- Conclusion: Ammonium Acetate (NH4CH3COO) gives an approximately neutral solution.
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About This Question
- Subject
- chemistry
- Chapter
- equilibrium
- Topic
- acid–base equilibria
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
NH4CH3COO
- Salt Hydrolysis Rules:
- Strong Acid + Strong Base (e.g., NaCl): No hydrolysis, pH=7.
- Strong Acid + Weak Base (e.g., NH4Cl): Cationic hydrolysis, pH<7 (Acidic).
- Weak Acid + Strong Base (e.g., CH3COONa): Anionic hydrolysis, pH>7 (Basic).
- Weak Acid + Weak Base (e.g., NH4CH3COO): Both ionize.
- Case of Ammonium Acetate: pH=7+21(pKa−pKb).
- Values: For acetic acid, pKa≈4.74. For ammonia, pKb≈4.75.
- Outcome: Since pKa≈pKb, the acidic and basic tendencies of the ions cancel each other out.
- Conclusion: Ammonium Acetate (NH4CH3COO) gives an approximately neutral solution.
This medium difficulty chemistry question is from the chapter equilibrium, covering the topic of acid–base equilibria. It appeared in the 2025 exam.
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