Work Function And Threshold
A metal cathode in a vacuum tube has a work function of 2.0 eV, and an engineer needs the threshold wavelength above which photoemission stops entirely.
Select the correct option:
Solution
Approximately 621 nm
The threshold wavelength marks the longest wavelength that can still just eject an electron, and NCERT defines it through ϕ=λ0hc, where ϕ is the work function. Rearranging gives λ0=ϕhc. Using the convenient constant hc=1242 eV·nm and ϕ=2.0 eV, we obtain λ0=2.01242=621 nm. Any wavelength longer than this carries too little energy per photon to overcome the work function, so emission ceases. The value 310 nm is wrong because it doubles the work function or halves the wavelength incorrectly, giving too short a threshold. The value 414 nm is wrong because it uses a work function of 3.0 eV rather than the stated 2.0 eV. The value 1242 nm is wrong because it forgets to divide by the 2.0 eV work function, leaving the bare constant. As stated in NCERT Class 12, Chapter 11, a smaller work function corresponds to a longer threshold wavelength, since less energy is needed to free an electron. Physically, the threshold wavelength is simply the wavelength at which each photon carries exactly the escape energy, leaving the electron with zero kinetic energy. Alkali metals such as caesium and sodium have low work functions and therefore long threshold wavelengths reaching into the visible, whereas metals like platinum need ultraviolet light to emit at all. A magnitude check confirms that a 2 eV barrier corresponds to red-orange light near 621 nm, a physically reasonable threshold for many metals.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- dual nature of matter and radiation
- Topic
- work function and threshold
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Approximately 621 nm
The threshold wavelength marks the longest wavelength that can still just eject an electron, and NCERT defines it through ϕ=λ0hc, where ϕ is the work function. Rearranging gives λ0=ϕhc. Using the convenient constant hc=1242 eV·nm and ϕ=2.0 eV, we obtain λ0=2.01242=621 nm. Any wavelength longer than this carries too little energy per photon to overcome the work function, so emission ceases. The value 310 nm is wrong because it doubles the work function or halves the wavelength incorrectly, giving too short a threshold. The value 414 nm is wrong because it uses a work function of 3.0 eV rather than the stated 2.0 eV. The value 1242 nm is wrong because it forgets to divide by the 2.0 eV work function, leaving the bare constant. As stated in NCERT Class 12, Chapter 11, a smaller work function corresponds to a longer threshold wavelength, since less energy is needed to free an electron. Physically, the threshold wavelength is simply the wavelength at which each photon carries exactly the escape energy, leaving the electron with zero kinetic energy. Alkali metals such as caesium and sodium have low work functions and therefore long threshold wavelengths reaching into the visible, whereas metals like platinum need ultraviolet light to emit at all. A magnitude check confirms that a 2 eV barrier corresponds to red-orange light near 621 nm, a physically reasonable threshold for many metals.
This medium difficulty physics question is from the chapter dual nature of matter and radiation, covering the topic of work function and threshold. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse dual nature of matter and radiation questions on RankGuru.