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Work Done By A Constant Force

Easyphysics

A warehouse worker pushes a crate along a level floor by applying a 50 N force directed at 60 degrees above the horizontal, displacing it 8 m. How much work does the applied force do?

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About This Question

Subject
physics
Chapter
work, energy and power
Topic
work done by a constant force
Difficulty
Easy
Year
2025
Tags
work doneconstant forceforce-displacement anglescalar productcosine component

Solution

Correct Answer:

200 J

Work done by a constant force equals the product of the force magnitude, the displacement, and the cosine of the angle between them, written . Only the component of force along the displacement transfers energy to the body; the perpendicular component does no work. Here the horizontal displacement is along the floor, so the relevant component of the 50 N force is . Multiplying by the 8 m displacement gives . The option 400 J wrongly uses the full force without the cosine factor. The option 346 J mistakenly uses , effectively swapping the angle. The option 100 J halves the correct displacement contribution and has no physical basis. This follows the NCERT definition of the scalar product of force and displacement. As a plausibility check, since the force is tilted away from the motion, the work must be less than the a fully horizontal force would deliver, and satisfies that bound.

This easy difficulty physics question is from the chapter work, energy and power, covering the topic of work done by a constant force. It appeared in the 2025 exam.

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