Work Done By A Constant Force
A warehouse worker pushes a crate along a level floor by applying a 50 N force directed at 60 degrees above the horizontal, displacing it 8 m. How much work does the applied force do?
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- work done by a constant force
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
200 J
Work done by a constant force equals the product of the force magnitude, the displacement, and the cosine of the angle between them, written W=Fdcosθ. Only the component of force along the displacement transfers energy to the body; the perpendicular component does no work. Here the horizontal displacement is along the floor, so the relevant component of the 50 N force is 50cos60∘=25 N. Multiplying by the 8 m displacement gives W=25×8=200 J. The option 400 J wrongly uses the full force without the cosine factor. The option 346 J mistakenly uses cos30∘, effectively swapping the angle. The option 100 J halves the correct displacement contribution and has no physical basis. This follows the NCERT definition of the scalar product of force and displacement. As a plausibility check, since the force is tilted away from the motion, the work must be less than the 400 J a fully horizontal force would deliver, and 200 J satisfies that bound.
This easy difficulty physics question is from the chapter work, energy and power, covering the topic of work done by a constant force. It appeared in the 2025 exam.
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