Work Done Against Friction
A block of mass 5 kg is pulled 10 m along a horizontal surface by a force. If the coefficient of kinetic friction is 0.2, how much work is done against friction? (g = 10 m/s²)
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- work done against friction
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
100 J
- Frictional Force (fk): fk=μkN. For a horizontal surface, N=mg.
- fk=0.2×5 kg×10 m/s2=10 N.
- Work Formula: Wf=Force×Displacement.
- Application:
- Wf=10 N×10 m.
- Result: Wf=100 Joules.
- Note: The energy dissipated by friction typically appears as internal energy (heat).
This medium difficulty physics question is from the chapter work, energy and power, covering the topic of work done against friction. It appeared in the 2025 exam.
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