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Work By A Position-dependent Force

Hardphysics

A single force directed along the x-axis varies with position as F = 3x^2 newtons and acts on a 1 kg particle initially at rest at the origin. What speed does the particle have after moving to x = 2 m?

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About This Question

Subject
physics
Chapter
work, energy and power
Topic
work by a position-dependent force
Difficulty
Hard
Year
2025
Tags
position-dependent forcework integrationwork-energy theoremvariable forcefinal speed

Solution

Correct Answer:

A force that depends on position requires integration to find its work, . Evaluating the integral gives . Since this is the only force, the work-energy theorem equates it to the gained kinetic energy: , so and . The option 8 m/s mistakes the work value in joules for the speed. The option 16 m/s reports rather than . The option 2 m/s arises from forgetting to integrate and using at a single point. The need for integration arises because the force is not constant over the displacement; multiplying its value at any single point by the distance would systematically misrepresent the true accumulated work. Geometrically, the integral of corresponds to the steadily growing area beneath a parabolic force curve, which weights later positions far more heavily than the early ones near the origin. This demonstrates the NCERT method of combining integration of a variable force with the work-energy theorem. As a check, the units of are , that is joules, and recovers the computed work.

This hard difficulty physics question is from the chapter work, energy and power, covering the topic of work by a position-dependent force. It appeared in the 2025 exam.

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