Vertical Circular Motion
A particle of mass 0.5 kg is moving in a vertical circle of radius 2 m. What is the minimum velocity at the highest point for the particle to complete the circle? (g = 10 m/s²)
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About This Question
- Subject
- physics
- Chapter
- work, energy and power
- Topic
- vertical circular motion
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
√20 m/s
- Critical Condition: At the highest point of a vertical circle, the minimum velocity is achieved when the string tension becomes zero (T=0).
- Force Balance: Centripetal force is provided by weight alone at this limit.
- mg=mv2/r.
- Isolate velocity: v=rg.
- Variables:
- r=2 m.
- g=10 m/s2.
- Calculation: v=2×10=20 m/s.
- Note: If v<rg, the particle will fall away from the circular path.
This hard difficulty physics question is from the chapter work, energy and power, covering the topic of vertical circular motion. It appeared in the 2025 exam.
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