Vernier Caliper
In a vernier caliper, 1 cm on the main scale is divided into 20 equal parts. If 25 divisions on the vernier scale coincide with 24 divisions on the main scale, what is the least count?
Select the correct option:
Solution
0.002 cm
- Main Scale Division (1MSD): 1 cm is divided into 20 parts.
- 1MSD=1/20=0.05 cm.
- Vernier Scale Division (1VSD): 25VSD=24MSD.
- 1VSD=(24/25)MSD.
- Least Count Formula: LC=1MSD−1VSD.
- Calculation:
- LC=1MSD−(24/25)MSD=(1/25)MSD.
- LC=0.05/25.
- Result: LC=0.002 cm.
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About This Question
- Subject
- physics
- Chapter
- units and measurements
- Topic
- vernier caliper
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
0.002 cm
- Main Scale Division (1MSD): 1 cm is divided into 20 parts.
- 1MSD=1/20=0.05 cm.
- Vernier Scale Division (1VSD): 25VSD=24MSD.
- 1VSD=(24/25)MSD.
- Least Count Formula: LC=1MSD−1VSD.
- Calculation:
- LC=1MSD−(24/25)MSD=(1/25)MSD.
- LC=0.05/25.
- Result: LC=0.002 cm.
This hard difficulty physics question is from the chapter units and measurements, covering the topic of vernier caliper. It appeared in the 2025 exam.
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