Variation Of G

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The height at which the acceleration due to gravity becomes g/9 (where g is surface gravity) in terms of Earth's radius R is:

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R/2

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Subject: physics
Chapter: gravitation
Topic: variation of g
Difficulty: Easy
Year: 2025

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Correct Answer:

Formula for g at height: $g^{'} = \frac{g}{( 1 + h / R ) ^{2}}$ .
Given condition: $g^{'} = \frac{g}{9}$ . $\frac{g}{9} = \frac{g}{( 1 + h / R ) ^{2}} ⟹ (1 + h / R)^{2} = 9$
Square root both sides: $1 + \frac{h}{R} = 3 ⟹ \frac{h}{R} = 2$ .
Result: $h = 2 R$ .

This easy difficulty physics question is from the chapter gravitation, covering the topic of variation of g. It appeared in the 2025 exam.

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Variation Of G

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