Transistor Action
In a properly operating npn transistor used for amplification, the base region is made extremely thin and lightly doped for a specific reason.
Select the correct option:
Solution
So that most injected electrons reach the collector instead of recombining in the base
NCERT explains that in an npn transistor operating in the active region the emitter-base junction is forward biased and the collector-base junction is reverse biased. The emitter injects a large number of electrons into the base, and because the base is made very thin and lightly doped, very few of these electrons find holes to recombine with there. Consequently the vast majority diffuse across the narrow base and are swept into the collector by its reverse-biased field, making the collector current nearly equal to the emitter current and the base current very small. The option that the base carries the largest share of emitter current is wrong because a thin lightly doped base deliberately keeps the base current tiny. The option that the collector junction becomes forward biased is wrong because active-region amplification requires the collector junction to be reverse biased. The option that emitter and collector currents become exactly equal is wrong because they differ by the small base current, so they are nearly but not exactly equal. As stated in NCERT Class 12, Chapter 14, the thin base ensures efficient carrier transfer to the collector. A consistency check confirms IE=IB+IC with IC≈IE.
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About This Question
- Subject
- physics
- Chapter
- electronic devices
- Topic
- transistor action
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
So that most injected electrons reach the collector instead of recombining in the base
NCERT explains that in an npn transistor operating in the active region the emitter-base junction is forward biased and the collector-base junction is reverse biased. The emitter injects a large number of electrons into the base, and because the base is made very thin and lightly doped, very few of these electrons find holes to recombine with there. Consequently the vast majority diffuse across the narrow base and are swept into the collector by its reverse-biased field, making the collector current nearly equal to the emitter current and the base current very small. The option that the base carries the largest share of emitter current is wrong because a thin lightly doped base deliberately keeps the base current tiny. The option that the collector junction becomes forward biased is wrong because active-region amplification requires the collector junction to be reverse biased. The option that emitter and collector currents become exactly equal is wrong because they differ by the small base current, so they are nearly but not exactly equal. As stated in NCERT Class 12, Chapter 14, the thin base ensures efficient carrier transfer to the collector. A consistency check confirms IE=IB+IC with IC≈IE.
This hard difficulty physics question is from the chapter electronic devices, covering the topic of transistor action. It appeared in the 2025 exam.
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