Total Internal Reflection
Light inside a diamond of refractive index 2.42 tries to escape into air, and a gemologist needs the critical angle beyond which total internal reflection occurs.
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- total internal reflection
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Approximately 24.4 degrees
Total internal reflection, discussed in NCERT, happens when light in a denser medium meets the boundary with a rarer medium at an angle exceeding the critical angle, defined by sinθc=ndensernrarer. For diamond to air, ndenser=2.42 and nrarer=1, so sinθc=2.421=0.413. Taking the inverse sine yields θc=sin−1(0.413)≈24.4∘. The unusually small critical angle explains why diamonds sparkle: light striking most internal facets exceeds this angle and is trapped, bouncing repeatedly before exiting. The value 41.8∘ is wrong because it corresponds to water (n=1.5 region) not diamond, using a lower index. The value 48.6∘ is wrong as it belongs to glass of index 1.33-type distractors, again the wrong medium. The value 65.6∘ inverts the ratio and takes the arcsine of 2.42, which is impossible since sine cannot exceed 1. As stated in NCERT Class 12, Chapter 9, a higher refractive index produces a smaller critical angle. A magnitude check confirms the very high index of diamond gives a strikingly small critical angle, consistent with its brilliant appearance.
This medium difficulty physics question is from the chapter optics, covering the topic of total internal reflection. It appeared in the 2025 exam.
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