Torque On A Current Loop
A rectangular coil of 20 turns and area 0.05m2 carries a current of 4A while placed in a uniform magnetic field of 0.3T with its plane parallel to the field. What torque acts on the coil?
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About This Question
- Subject
- physics
- Chapter
- magnetic effects of current and magnetism
- Topic
- torque on a current loop
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
1.2N m
A current loop in a uniform field experiences a torque τ=NIABsinθ, where θ is the angle between the magnetic moment (the normal to the coil plane) and the field. When the plane of the coil is parallel to the field, the normal is perpendicular to the field, so θ=90∘ and sinθ=1, giving maximum torque. Substituting N=20, I=4A, A=0.05m2 and B=0.3T, we get τ=(20)(4)(0.05)(0.3)(1)=1.2N m. The option 0.6N m wrongly inserts sin45∘ or halves a factor. The option 0N m would apply only if the plane were perpendicular to the field, where the normal aligns with B. The option 2.4N m doubles the turns. This is the operating principle of the moving-coil galvanometer in NCERT. A sanity check confirms newton-metre units and that the torque is greatest precisely when the plane lies along the field. The same physics underlies every electric motor: the torque tends to rotate the coil until its magnetic moment aligns with the field, and a commutator reverses the current each half-turn to keep the rotation continuous. In a galvanometer, by contrast, a spiral spring supplies a restoring torque so the coil settles at a deflection proportional to current, converting the rotational tendency described here into a steady, readable measurement of current.
This medium difficulty physics question is from the chapter magnetic effects of current and magnetism, covering the topic of torque on a current loop. It appeared in the 2025 exam.
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