Torque
A mechanic applies a 40 N force perpendicular to the free end of a wrench of length 0.25 m in order to loosen a tight bolt. What is the magnitude of the torque produced about the bolt?
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About This Question
- Subject
- physics
- Chapter
- rotational motion
- Topic
- torque
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
10 N m
Torque is the rotational analogue of force and is given by τ=rFsinθ, where r is the distance from the axis to the point of application and θ is the angle between the force and the position vector. Since the mechanic pushes perpendicular to the wrench, θ=90∘ and sinθ=1, so the entire force is effective in turning the bolt. Then τ=(0.25 m)(40 N)(1)=10 N m. The value 16 N m has no consistent physical origin and appears to mix unrelated numbers. The value 5 N m would result from halving the lever arm without any justification. The value 100 N m wrongly multiplies the force by 2.5 instead of 0.25, a place-value error. This is the direct NCERT definition of the moment of a force about a point, the quantity that produces angular acceleration. As a unit check, multiplying newtons by metres yields newton-metres, the correct dimension of torque, and the modest lever arm sensibly gives a modest turning effect of 10 N m.
This easy difficulty physics question is from the chapter rotational motion, covering the topic of torque. It appeared in the 2025 exam.
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