Time Period Of Satellite
A satellite revolves in a circular orbit where the radius is 10⁷ m and the acceleration due to gravity is 10 m/s². What is its time period?
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About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- time period of satellite
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
2π × 10³ s
- Centripetal acceleration: The local value of gravity g′ at that path provides the needed radial acceleration.
- g′=rv2⟹v=g′r.
- Velocity Formula: v is the speed of traversal.
- Period Definition: T=v2πr=g′r2πr=2πg′r.
- Apply Numbers:
- T=2π10107=2π106.
- Final Value: T=2π×103 seconds.
This medium difficulty physics question is from the chapter gravitation, covering the topic of time period of satellite. It appeared in the 2025 exam.
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