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Terminal Velocity And Stokes' Law

Mediumphysics

A small steel ball falling vertically through a tall column of viscous oil eventually moves at constant speed. If a second ball of the same material but twice the radius is dropped through the identical oil, how does its terminal velocity compare?

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About This Question

Subject
physics
Chapter
properties of solids and liquids
Topic
terminal velocity and stokes' law
Difficulty
Medium
Year
2025
Tags
terminal velocityStokes' lawviscous dragradius dependencebuoyancy balance

Solution

Correct Answer:

Four times that of the first ball

Terminal velocity is reached when the downward weight of the sphere is balanced by the upward buoyant force and the viscous drag described by Stokes' law, . Setting net force to zero gives , which rearranges to . For balls of the same material in the same oil, every factor except the radius is fixed, so . Doubling the radius therefore multiplies the terminal velocity by . The option 'same' ignores the radius dependence entirely. The option 'twice' assumes a linear rather than quadratic relation. The option 'half' even gives the wrong direction, since a larger ball falls faster. This quadratic dependence on radius is the central result of the NCERT treatment of viscous fall, and it holds only while the motion stays laminar so that Stokes' linear drag law applies. The weight of the sphere grows as whereas the viscous drag grows only as , so their balance forces the steady speed to climb as . As a check, larger raindrops and hailstones are known to reach higher steady speeds than tiny droplets, which agrees with the strong growth obtained here.

This medium difficulty physics question is from the chapter properties of solids and liquids, covering the topic of terminal velocity and stokes' law. It appeared in the 2025 exam.

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