Skip to content

Term From The End

Easymathematics

In the expansion of (a + b)^{17}, a problem asks which numbered term counted from the beginning coincides with the 5th term counted from the very end of the expansion.

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

More binomial theorem and its simple applications Practice Questions

EasyJEE_ADVANCED

Using the first-order binomial approximation for small quantities, the approximate value of (1.002)^...

View Solution→
MediumJEE_ADVANCED

When the trinomial (1 + x + x^2)^{3} is expanded completely into a polynomial in x, the coefficient ...

View Solution→
MediumJEE_ADVANCED

If the expansion of (1 + x)^n is split into terms with even index and terms with odd index, the sum ...

View Solution→
HardJEE_ADVANCED

Within the expansion of (\sqrt{3} + \sqrt[3]{2})^{6}, the number of terms that turn out to be ration...

View Solution→
HardJEE_ADVANCED

Suppose the coefficients of three consecutive terms in the expansion of (1 + x)^n are in the ratio 1...

View Solution→
HardJEE_ADVANCED

By differentiating a standard expansion and substituting suitably, the weighted sum C(n,1) + 2 C(n,2...

View Solution→
HardJEE_ADVANCED

Through integrating the binomial expansion over a unit interval, the alternating series C(n,0)/1 - C...

View Solution→
MediumJEE_ADVANCED

Treating the binomial theorem for a negative index, the coefficient of x^3 in the series expansion o...

View Solution→
MediumJEE_ADVANCED

For the numerical expansion of (1 + x)^{n} with specific values applied, the greatest term is identi...

View Solution→
EasyJEE_ADVANCED

Using the binomial theorem to analyse remainders, the quantity 7^{83} is divided by 6 and the result...

View Solution→
HardJEE_ADVANCED

When the very large number 3^{100} is computed and its final two digits are examined, the binomial t...

View Solution→
MediumJEE_ADVANCED

A question requires the coefficient of x^5 in the product expansion of (1 + x)^4 multiplied by (1 + ...

View Solution→

Browse all binomial theorem and its simple applications questions →

About This Question

Subject
mathematics
Chapter
binomial theorem and its simple applications
Topic
term from the end
Difficulty
Easy
Year
2025
Tags
advanced-calculus-drillterm-from-endterm-indexingexpansion-symmetrycounting-terms

Solution

Correct Answer:

14th term

Counting terms from the end is converted to counting from the start using the rule that the rth term from the end is the (n - r + 2)th term from the beginning in an expansion of (a + b)^n, a useful JEE Advanced symmetry observation. The expansion of (a + b)^{17} has n + 1 = 18 terms in total. The 5th term from the end is the (18 - 5 + 1)th = 14th term from the beginning, since position from start plus position from end equals total terms plus one. Hence the 5th term from the end is the 14th term from the beginning. Option 13th term miscounts by one, forgetting the plus one in the indexing. Option 12th term subtracts incorrectly. Option 15th term overshoots the position. The relation position-from-start + position-from-end = total + 1 is the controlling identity. Plausibility check: the 14th term from the start and the 5th term from the end together give 14 + 5 = 19 = 18 + 1, exactly matching the total-terms-plus-one rule, which confirms consistency.

This easy difficulty mathematics question is from the chapter binomial theorem and its simple applications, covering the topic of term from the end. It appeared in the 2025 exam.

Looking for more practice? Explore all mathematics questions or browse binomial theorem and its simple applications questions on RankGuru.